for i in range(1,101): print "FizzBuzz" if not i % 15 else "Fizz" if not i % 3 else "Buzz" if not i % 5 else str(i)

Even a little shorter :)

And a bit shorter still :D. Down to 102 chars now.

    for i in range(1,101):print "Fizz" if not i%3 else '' + "Buzz" if not i%5 else str(i) if (i%3) else ''

Edit: Down to 82 characters now. I'm not sure if this would work on every Python, but it works on mine.

    for i in range(1,101):print(("Fizz"if i%3==0 else'')+("Buzz"if i%5==0 else''))or i

You can drop the extra () which brings it down to 80.

  for i in range(1,101):print("Fizz"if i%3==0 else'')+("Buzz"if i%5==0 else'')or i

74

    for i in range(1,101):print(''if i%3 else'Fizz')+(''if i%5 else'Buzz')or i

70 now, still same idea.

    for x in range(1,101):print['','Fizz'][x%3==0]+['','Buzz'][x%5==0]or x

Excellent. Down to 68.

    for x in range(1,101):print['','Fizz'][x%3<1]+['','Buzz'][x%5<1]or x

My shortest Python solution is 59 characters. Two tricks, use while instead of range, and use string repetition instead of lists

  n=1
  while n<101:print'Fizz'*(n%3<1)+'Buzz'*(n%5<1)or n;n+=1

And here is a wacky one in 96 chars

  w=range(101)
  w[::3]=['Fizz']*34
  w[::5]=['Buzz']*21
  w[::15]=['FizzBuzz']*7
  for s in w[1:]:print s

You can save one more character with an exec loop

  n=1;exec"print'Fizz'*(n%3<1)+'Buzz'*(n%5<1)or n;n+=1;"*100

Nice, The 82 character one works for me also, on Mac OS X python 2.7.3