Fizz Buzz codegolf challenge in 15 languages

Re:Fizz Buzz codegolf challenge in 15 languages by y2bd on Friday December 14, 2012 @05:43PM (#4923771)

70 now, still same idea.

    for x in range(1,101):print['','Fizz'][x%3==0]+['','Buzz'][x%5==0]or x

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Re:Fizz Buzz codegolf challenge in 15 languages by GregBuchholz on Friday December 14, 2012 @05:55PM (#4923818)

Excellent. Down to 68.

    for x in range(1,101):print['','Fizz'][x%3<1]+['','Buzz'][x%5<1]or x

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Re:Fizz Buzz codegolf challenge in 15 languages by twiceaday on Sunday December 16, 2012 @10:43PM (#4930723)

My shortest Python solution is 59 characters. Two tricks, use while instead of range, and use string repetition instead of lists

  n=1
  while n<101:print'Fizz'*(n%3<1)+'Buzz'*(n%5<1)or n;n+=1

And here is a wacky one in 96 chars

  w=range(101)
  w[::3]=['Fizz']*34
  w[::5]=['Buzz']*21
  w[::15]=['FizzBuzz']*7
  for s in w[1:]:print s

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Re:Fizz Buzz codegolf challenge in 15 languages by ajennings on Tuesday December 18, 2012 @01:04PM (#4938651)

You can save one more character with an exec loop

  n=1;exec"print'Fizz'*(n%3<1)+'Buzz'*(n%5<1)or n;n+=1;"*100

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