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Re:1/0 = 0 (2018) by quantified on Monday December 02, 2024 @07:03PM (#42301745)
One intuition could be: As you divide 1 by negative numbers of smaller and smaller magnitude, you get negative numbers of increasing magnitude. At 0, the positive infinity of 1/0 is met by the negative infinity of 1/-0 and their average is 0.
Re:1/0 = 0 (2018) by behnamoh on Tuesday December 03, 2024 @03:55PM (#42311284)
why take averages?
Re:1/0 = 0 (2018) by quantified on Wednesday December 04, 2024 @12:09AM (#42314627)
Well, it would be simultaneously at both extremes.