Re:1/0 = 0 (2018)
by quantified on Monday December 02, 2024 @07:03PM
(#42301745)
One intuition could be: As you divide 1 by negative numbers of smaller and smaller magnitude, you get negative numbers of increasing magnitude. At 0, the positive infinity of 1/0 is met by the negative infinity of 1/-0 and their average is 0.
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why take averages?
Re:1/0 = 0 (2018)
by quantified on Wednesday December 04, 2024 @12:09AM
(#42314627)
Well, it would be simultaneously at both extremes.