Don't think you can do $i%15, still need to do that check separately. I like how you can leave out the closing ?>. you can also save 2 spaces by getting rid of whitespace between statements and symbols .

The comments on the RapLeaf blog post I linked to in this thread has a guy trying out different Ruby solutions. Very clever!

That code produces correct output. It passed.

PHP does not require a closing ?>

Ohhh. I was thinking about it wrong. Probably obvious to others, but I forgot about the property that if you have primes p and q, any number n (evenly) divisible by p that is also divisible by q must be divisible by the product of p*q.

That shortcut is a result of hyper-optimization and I was thinking more along the lines of code-reusability (e.g. if the rules of FizzBuzz were changed from %3 and %5 to %x and %y) =P

I only worked on it for a few minutes and got 114 chars in Python

  for i in range(1,101):
   if i%15==0:print'FizzBuzz'
   elif i%3==0:print'Fizz'
   elif i%5==0:print'Buzz'
   else:print i

Now I am on the hunt to figure out how to do it in 56, there goes my afternoon.

Heh, shortest I could do in Python after several hours was 62

  for x in range(1,101):print'Fizz'*(x%3==0)+'Buzz'*(x%5==0)or x

Off by 6 bytes!