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Re:Upcoming/proposed breaking changes to Haskell by olliej on Wednesday November 17, 2021 @08:08PM (#29260969)
that's a default implementation, however it's not true for every type, hence custom implementations
Re:Upcoming/proposed breaking changes to Haskell by kreetx on Thursday November 18, 2021 @03:49AM (#29263455)
Right. With the current situation you could define a custom /= for every type. In the new situation /= is a regular function which is defined as `a /= b = not (a == b)` and you wouldn't be able to redefine it.