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Re:0.999...= 1 by iso1631 on Tuesday April 28, 2020 @03:37AM (#23004499)
Another secondary school 'proof'

  x = 0.9999.....
  10x = 9.9999.....
  (10x -x) = 9x = (9.9999.... - 0.9999....) = 9
  x = 9/9 = 1
Re:0.999...= 1 by notRobot on Tuesday April 28, 2020 @03:52AM (#23004624)
or,

      x = 0.9999...
    10x = 9.999...
    10x = 9 + 0.999...
    10x = 9 + x
     9x = 9
      x = 1
Presented slightly more clearly

https://en.wikipedia.org/wiki/0.999...#Algebraic_arguments

Re:0.999...= 1 by hinkley on Tuesday April 28, 2020 @04:04AM (#23004723)
Yeah that’s way more complicated than it needs to be and I’m tempted to replace that whole section with:

x = 0.9999...

2x = 1.9999...

2x - x = 1

x = 1

Re:0.999...= 1 by moonchild on Tuesday April 28, 2020 @04:15AM (#23004800)
It's much more intuitive that 100.9999...=9.9999... than that 20.9999...=1.9999...
Re:0.999...= 1 by ColinWright on Tuesday April 28, 2020 @10:56AM (#23007592)
You've met the formatting limitations. You mean:

"It's much more intuitive that 10 * 0.9999... = 9.9999... than that 2 * 0.9999...= 1.9999..."

Re:0.999...= 1 by champagneben on Tuesday April 28, 2020 @04:15AM (#23004801)
How do you jump from

x = 0.999...

to

2x = 1.999..

Re:0.999...= 1 by hinkley on Tuesday April 28, 2020 @01:29PM (#23009442)
Picture an infinite ticker tape in your mind.

Write

   0.9
 + 0.9
 —————-
   1.8

Now keep extending the 9’s. You have to carry a one, so fix the carry and then add more nines.

Where people keep getting tripped up is thinking you can stop when you get tired, or die, or when the universe ends in heat death. You don’t get to stop. You never get to stop. It’s nines all the way down.

Re:0.999...= 1 by saagarjha on Tuesday April 28, 2020 @04:25AM (#23004880)
It’s less intuitive, but still relatively straightforward from performing the “long” multiplication. You do need to convince people that the “8 at the end“ is irrelevant, however.
Re:0.999...= 1 by hinkley on Tuesday April 28, 2020 @01:15PM (#23009234)
You need to convince people there is no 8 at the end because there is no end.

If you see an 8 it’s because you didn’t carry the 1. Keep going.

Another way to think about it is that you have n digits, and I’m using the n and n + 1 digit at the same time. But since n goes to infinity, +1 hardly matters.

Re:0.999...= 1 by syockit on Tuesday April 28, 2020 @11:15AM (#23007774)
The difficult part is to convince that (9.9999.... - 0.9999....) = 9. Someone else mentioned about Zeno's paradox involving Achilles and the tortoise. Since you multiplied x by 10 to get 9.9999...., you know that it's always going to be 1 decimal place slower in pace to reach convergence compared to 0.9999.... What you might get instead is (9.9999.... - 0.9999....) = 8.9999....
Re:0.999...= 1 by himinlomax on Tuesday April 28, 2020 @06:53AM (#23005702)
I like this one better:

    0.9        = 1 - 0.1
    0.99       = 1 - 0.01
    0.999      = 1 - 0.001
    0.9999     = 1 - 0.0001
    0.99999... = 1 - 0.00000... with a 1 at the end of the infinite series of 0
Re:0.999...= 1 by jayd16 on Tuesday April 28, 2020 @09:48AM (#23006902)
>[...] at the end of the infinite series of [...]

...uhh

Re:0.999...= 1 by himinlomax on Wednesday April 29, 2020 @07:52AM (#23018036)
"Eternity feels a bit too long ... especially near the end."
Re:0.999...= 1 by pgtan on Tuesday April 28, 2020 @10:03AM (#23007053)
> 10x -x

subtracting infinities is dangerous, you can achieve any result from it

https://www.youtube.com/watch?v=-EtHF5ND3_s

Re:0.999...= 1 by OskarS on Tuesday April 28, 2020 @10:37AM (#23007392)
You're not subtracting anything infinite. Whatever you think of 0.99999... (and the correct thing to think is that it equals 1), I hope we can both agree that it is at least finite! I mean, we can agree that it's less than 2 and more than 0, right?

That subtraction is just as valid as saying 0.333... + 0.333... = 0.666..., or that 1/3 + 1/3 = 2/3.