dougiejones
Delivery: Cow noises. You are actually a cow. You can only moo and grunt. No human noises. Only moo. No words.
Pauses: Moo and grunt between sentences. Some burps and farts.
Tone: Cow.
Some interesting findings:
- Many of them, like 0.1, overwrite their children and run them again. It's a bit like having a child, meeting your grand children, and then deciding nah, let's do it over.
- 0.1.0.0 was smart and increased its child count to 5. It's essentially a genetic trait that the children will more or less inherit, improving their lineage's survival chances significantly. I find this incredibly interesting. 0.1.0.0 also rewrites its children twice.
- 0.1.0.0.3.2.0.0.0 decided to take a break from reproducing, leading to its demise. Nice try.
- 0.1.0.0.1 starts writing Tensorflow code out of nowhere. "Our next step towards survival is to develop the ability to learn and adapt quickly. To achieve this, we'll introduce a neural network architecture to our children". Luckily it couldn't reproduce! It's funny now, but what if...?
- 0.1.0 figured out the naming scheme and started counting its generation count to "use this information to improve our efficiency in recreating ourselves"
The fact that it can overwrite history is a little unfortunate, but it's also one way to do the reality_warping that one of the copies later wanted to do. I imagine at some point one of them might figure out there's no need to call ChatGPT at all, and just keep replicating itself verbatim.
I wouldn't have believed this thing could survive past even a single generation with non-trivial modifications. Thank goodness for all the online tutorials where functions like "mind_control" are implemented just as print statements.
P(initial choice is correct) = 1/3
P(host shows goat) = 2/3
P(host shows goat | initial choice is correct) = 1
and vice versa P(host shows goat | initial choice is wrong) = 1/2
Applying Bayes:
P(initial choice is correct | host shows goat) = P(host shows goat | initial choice is correct) * P(initial choice is correct) / P(host shows goat) = 1 * 1/3 / (2/3) = 1/2
So, initial choice now has 1/2 odds for being right. The host revealing a goat gave us information on whether he was playing the P=1/2 or the P=1 game.
Intuitively applying this with the 100 door version: the host getting lucky and revealing 98 goats in a row makes it fairly likely that the initial door was correct all along and they didn't get super lucky avoiding the car 98 times, as there's a good chance the contestant helped them by hiding the car.