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A comment on Flexbox in 5 minutes. Parent comment

Re:Flexbox in 5 minutes by Excavator on Wednesday March 04, 2015 @01:07PM (#9146112)
As I recall it, the available space is divided by the sum.

So in this case the width for "2" would be: 2 * (available_width / (1 * other_items + 2))

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