C Legacy Is Evil

Re:C Legacy Is Evil by dezgeg on Tuesday November 04, 2014 @04:33PM (#8559157)

There's also a way to do this without any user-defined functions that works in both C and C++:

    struct tm tm_struct = { 0, };

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Re:C Legacy Is Evil by cremno on Tuesday November 04, 2014 @04:40PM (#8559203)

In ISO C++ and GNU C you can also omit the 0:

    struct tm tm_struct = { };

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Re:C Legacy Is Evil by JoeAltmaier on Tuesday November 04, 2014 @04:42PM (#8559216)

Does that work on char array members in the struct?

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Re:C Legacy Is Evil by dezgeg on Tuesday November 04, 2014 @04:47PM (#8559253)

Yes, as far as I believe, this should always work in standard C89/C99. In the char array case, it works due to the brace elision rule in aggregates: assuming

    struct foo { char bar[3]; };

These declarations are equivalent:

    struct foo f1 = { 0, };
    struct foo f2 = { { 0, } };

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Re:C Legacy Is Evil by readerrrr on Tuesday November 04, 2014 @04:45PM (#8559239)

In C, using: struct tm tm_struct = { 0 } ;, the rest of the struct including padding is initialized to zero bits.

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