Honestly that is more important to my mental model of the 1D Fourier transform than the algebraic description. It may be slightly inaccurate (are we talking projection or decomposition when calculating the settings on that tide predictor? for example).
2D Fourier transform is more interesting to me as it has applications in graphics. For example, you can synthesise ocean wave-like patterns in a height field by generating a noise image, shaping the noise into a slightly modified disc around the origin, and doing an IFFT. Intuitively you get random wavelength components within a given range, with random orientations. I couldn't write you a formula for that. You can imagine that a 12 year old could understand it, thought. Old paper is here: http://www.computer.org/csdl/mags/cg/1987/03/mcg1987030016.p... Another intuitively comprehensible 2D trick is to use an FFT to implement a simulation of fluid dynamics. That's a more complex one but again, it can be understood without algebra. http://www.dgp.toronto.edu/people/stam/reality/Research/pdf/...
And then you realize -- hey, those are exponentials -- so the rule that integrating/differentiating each component is trivial allows you to solve linear ODE really quickly.
I don't think algebra gets in the way at all -- it just makes this decomposition crystal clear. It makes generalizing easy also -- there are other nice basis like cosine basis, and so on. You can choose any N functions to decompose your N-point function, as long as they are linearly independent, you're guaranteed perfect reconstruction.
Algebra is definitely necessary and useful here, but the concepts can be learnt without knowing algebra, which means they are open to a lot more people.
Unfortunately, yes. The linked article even avoids this language at all costs. And that's just how people work in physics and engineering. They want to talk about spinning functions and all this nonsense instead of just doing some basic linear algebra.
Once you learn enough about mathematics, and here linear algebra, you will start to reduce more complicated concepts to more simple concepts to build the complex ideas up from simple ones. In this case, the notion of a change of basis is definitely much simpler than the notion of an integral transform, so it makes sense to express it that way.
"What it actually calculates" can be a tricky topic in mathematics. It calculates what we want it to calculate, that's how people came up with the definition. So the way to understand "what it calculates" is to understand "what do I want it to calculate". Somewhat like programming, really. If we want to calculate a function's representation in a convenient basis, then that's what we'll make Fourier transform do.
Both of them explain different things. The "it's just a basis transformation" makes invertibility, additivity, etc. obvious. The spinning function things makes it clear why we want to do it and what it means to say, approximate by only the small frequencies. (The basis thing tells you nothing about why looking at just the low coefficients is helpful, sometimes. A basis doesn't care about ordering)
Except for orientability, I guess.
But most ECE undergrads will first see the Fourier transform in a continuous setting. Then it isn't so much an issue of "basic linear algebra"- students have almost certainly never talked about the space of square integrable functions, the inner product on this space, a basis for continuous functions, what it means for an infinite collection of objects to be orthogonal, etc... That is, if they have even taken any linear algebra yet!
Students learn to associate "Fourier Transform" with "complicated math" and then are discouraged when they learn about the DFT. At least, that has been my experience when TAing signal processing classes.
I always thought this was the definition of Fourier transform, and all the stuff with integrals was just to express the change of basis in an explicit form. What else would the word "transform" mean?
How is it even possible for someone to learn about the Fourier transform without it being very explicitly said that it is a change of basis to a different set of orthogonal functions? Did they just introduce the integral expression for it and hope people would memorize it? I don't understand.