> although it will still be missing make_unique<T[]>
This is not true -- see §20.9.1.4 of the C++14 draft [1]. make_unique is defined for array types with unknown bound (i.e., T[]), but it is deleted for array types of known bound (e.g., T[5]). So to make an array of 100 default-initialized `int`s,
auto array = std::make_unique<int[]>(100);
2. As you mentioned, make_unique is a part of C++14 (although it will still be missing make_unique<T[]> ). I don't see the big deal is though since libc++, libstdc++, and VS2013 already have a compliant make_unique implementation.