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Re:P = NP by Gurkenglas on Wednesday December 04, 2013 @07:19AM (#6846403)
I think the statement you meant to remind us of is that NP is a subset of PSPACE.
Re:P = NP by jessaustin on Wednesday December 04, 2013 @07:31AM (#6846440)
According to the paper under discussion, the two statements are equivalent. Your version is probably more graceful, however.