Re:P = NP
by jessaustin on Wednesday December 04, 2013 @07:06AM
(#6846366)
In addition to what siblings said, remember that P is a subset of PSPACE.
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Re:P = NP
by Gurkenglas on Wednesday December 04, 2013 @07:19AM
(#6846403)
I think the statement you meant to remind us of is that NP is a subset of PSPACE.
Re:P = NP
by jessaustin on Wednesday December 04, 2013 @07:31AM
(#6846440)
According to the paper under discussion, the two statements are equivalent. Your version is probably more graceful, however.