Re:Why Mathematica does not simplify Sinh[ArcCosh[x]]
by yorwba on Sunday March 15, 2026 @06:21AM
(#47385968)
For x = -i, square(x) = -1, sqrt(square(x)) = i. Meanwhile, abs(x) = 1. You're right that it simplifies to abs(x) for real x, but that no longer holds for arbitrary complex values.
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Re:Why Mathematica does not simplify Sinh[ArcCosh[x]]
by NooneAtAll3 on Sunday March 15, 2026 @09:12AM
(#47387069)
for arbitrary complex values sqrt() gives 2 answers with +- signs
so sqrt(square(-i)) = +-i, one of which is x
Re:Why Mathematica does not simplify Sinh[ArcCosh[x]]
by Armisael16 on Sunday March 15, 2026 @12:18PM
(#47388862)
The sqrt function returns the principle square root, not both. That’s true for all numbers, positive, negative, and complex alike.