First, the code claims to be returning "unsigned long" from each of these functions, but the value will only ever be 0 or 1 (see [1]). The code is actually throwing away the result and just returning whether overflow occurred. If we take unsigned long *c as another argument to the function, so that we actually keep the result, we end up having to issue an extra instruction for multiplication (see [2]; I'm ignoring the sd instruction since it is simply there to dereference the *c pointer and wouldn't exist if the function got inlined).
Second, this is just unsigned overflow detection. If we do signed overflow detection, now we're up to 5 instructions for add and mul (see [3]). Considering that this is the bigger challenge, it compares quite unfavorably to architectures where this is just 2 instructions: the operation itself and a branch against a condition flag.
[1]: https://gcc.gnu.org/onlinedocs/gcc/Integer-Overflow-Builtins...
It's just a bizarre design choice. I understand wanting to get rid of condition flags, but not replacing them with nothing at all.
EDIT: It seems the same choice was made by MIPS, which is a clear inspiration for RISC-V.
1. 64 bit signed math is a lot less overflow vulnerable than the 16/32 bit math that was extremely common 20 years ago
2. For the BigInt use-case, the Riscv design is pretty sensible since you want the top bits, not just presence of overflow
3. You can do integer operations on the FPU (using the inexact flag for detecting if rounding occurred).
4. Adding overflow detecting instructions can easily be done in an extension in the future if desired.
Read the RISC-V documentation to see that you need at least 3 instructions.
For addition, overflow happens when you add 2 positive numbers and the result is negative, or when you add 2 negative numbers and the result is positive.
After using an instruction to do the addition, how can you detect this complex condition with a single instruction in the impoverished RISC-V ISA?
EDIT: Someone has downvoted this, presumably because I have not been polite enough.
That may be true, but I consider much more impolite the kind of misleading false information that has been written by the poster to whom I have replied. It is difficult to read that kind of b*s*t and be cool about it.
this just isn't true. both addition and multiplication can check for overflow in <2 instructions.