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Re:Memory access is O(N^[1/3]) by pfortuny on Wednesday October 08, 2025 @03:02PM (#45519450)
Yes, the notation seems wrong but it is because O(...) is a set, not a function. The functions is what goes inside.

So it should be f€O(...) instead of f=...

(don't know how to write the "belongs" symbol on iOS).

Re:Memory access is O(N^[1/3]) by singhrac on Wednesday October 08, 2025 @03:21PM (#45519632)
Here you go: ∈ (so f ∈ (...))
Re:Memory access is O(N^[1/3]) by pfortuny on Friday October 10, 2025 @02:31AM (#45535906)
That helps but how do I learn it?