Re:WASM 3.0 Completed
by brokencube on Wednesday September 17, 2025 @06:39PM
(#45282277)
I would guess 3 colour channels at 16bit (i.e. 2 bytes)
(2^32)÷(1920×1080×4×3×2) = 86
Where does the 4 come from? I thought it was R+G+B+A, but you already have 3 colour channels in that calculation
Re:WASM 3.0 Completed
by brokencube on Thursday September 18, 2025 @05:39AM
(#45287595)
Yep, my logic is faulty there. And even if we assume that it's 24bpp color, that's still a factor of 2 out.
Apparently with 24 bytes per pixel instead of bits :)
Although to be fair, there's HDR+ and DV, so probably 4(RGBA/YUVA) floats per pixel, which is pretty close..
How is that data stored?
Because (2^32)÷(1920×1080×4) = 518 which is still low but not 86 so I'm curious what I'm missing?