Re:Standard Thermal: Energy Storage 500x Cheaper Than Batteries
by Cthulhu_ on Monday August 25, 2025 @10:18AM
(#45014146)
Please don't cite ChatGPT as a source or as a caveat, instead show the actual math, which should only be about high school level; kinetic energy formula ½mv² = e,
In perfect conditions assuming no loss through drag, you're looking at the kinetic energy formula which is ½mv² = E (in joules).
E = 1 kWh = 3,600 kilojoules, velocity v at 10 meters is 14 m/s, so we need to calculate m for v = 14 and E = 3600k, which is just under 36735 kg. "about four of those blocks" is "about" correct.
Re:Standard Thermal: Energy Storage 500x Cheaper Than Batteries
by michaelgburton on Monday August 25, 2025 @11:19AM
(#45014826)
Simpler to use the potential energy formula, surely.
E = mgh
m = E/gh
m = 3.6 * 10^6 J / (9.8 m/s^2 * 10m) = 3.6735 * 10^4 kg
Re:Standard Thermal: Energy Storage 500x Cheaper Than Batteries
by wickedsight on Thursday August 28, 2025 @05:02AM
(#45050003)
This is exactly what ChatGPT provided. Me, the person, then chose to describe it as 'about 4'.
If you'd want to store 1kWh at 10m height, assuming no loss at all from heat, friction, etc, you'd need about 4 of those blocks block weighing 10 tons (according to ChatGPT). So you'd need a lot of those blocks to power a house for a day, unless you're very efficient.