Re:Swirling Forces, Crushing Pressures Measured in the Proton
by gus_massa on Thursday March 14, 2024 @10:48PM
(#39711577)
It's not very clear and this is not my area, but I think it's relevant that the proton has spin != 0. [1]
<guess> I think that the graphic assumes that the spin on the proton is pointing up (perpendicular to the sheet of paper) and the forces that are drawn are parallel to the "equator". In the "north pole"and "south pole" there are no forces.</guess>
[1] The spin is 1/2, but I guess the exact value is not important for this, only that it's not null.
<guess> I think that the graphic assumes that the spin on the proton is pointing up (perpendicular to the sheet of paper) and the forces that are drawn are parallel to the "equator". In the "north pole"and "south pole" there are no forces.</guess>
[1] The spin is 1/2, but I guess the exact value is not important for this, only that it's not null.