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Re:How random is xkcd? (2015) by tedunangst on Thursday December 28, 2023 @01:34PM (#38796792)
What do you do when it's 15:7?
Re:How random is xkcd? (2015) by Dylan16807 on Thursday December 28, 2023 @02:01PM (#38797151)
Then you probably want to calculate the attacks between two big blobs of units without separating them. But the result is still going to be "something like 7 simultaneous 2:1 battles", and not at all like 30% odds of upset.