That's really cute, but it's also buggy. The loop will start at i == 41.

You are right about it starting on 41, but chances are that that is its intended behavior, with a bit of context that is more clear:

  #define ARRAYSIZE 42

  int array[ARRAYSIZE];

  void f() {
     for (i=ARRAYSIZE; i --> 0;) {
       printf("%d\n", array[i]);
     }
  }

If it were to start at 42 you'd be referencing the array outside of its bounds.

In C you're used to less-than-one loops though. for(i = 0; i < 5; i++) terminates on 4. And it's what you want if you're going through an array.

The observant (yeah, newbies aren't so much, typically) will note that it really shouldn't be called "goes to" because it doesn't work the other way:

   for(int i=0; i --> 42;) { bar(); }