> But compilers I am an expert in and what you're implying is impossible

> it is either resolved statically or at runtime

Just tell Lisp which calls to statically resolve, inline, optimize. Overwrite the global default.

  (defun foo (a)
    (declare (inline +)
             (optimize (speed 3))
             (type (integer 0 100) a))
    (* 10 (+ 3 a)))

Above tells Lisp to inline the + function, optimize for speed and declares the type of a to be an integer in the range 0 to 100.

  * (disassemble #'foo)
  ; disassembly for FOO
  ; Size: 32 bytes. Origin: #x7006DC8544  ; FOO
  ; 44:       40190091         ADD NL0, R0, #6
  ; 48:       5C0180D2         MOVZ TMP, #10
  ; 4C:       0A7C1C9B         MUL R0, NL0, TMP
  ; 50:       FB031AAA         MOV CSP, CFP
  ; 54:       5A7B40A9         LDP CFP, LR, [CFP]
  ; 58:       BF0300F1         CMP NULL, #0
  ; 5C:       C0035FD6         RET
  ; 60:       E00120D4         BRK #15    ; Invalid argument count trap

As you can see in the machine code, Lisp then uses the native machine code ADD and MUL instructions.