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Re:Revisiting the Fast Inverse Square Root – Is It Still Use... by stephencanon on Friday April 21, 2023 @07:43PM (#35661725)
Division is actually pretty straightforward: compute a residual using the multiply-add that you already have, divide _that_, and then add it to the quotient.

Or (roughly equivalently, but maybe easier to understand) do a native double division, then do a Newton-Raphson step, which requires only multiplication and addition (just like you would refine a reciprocal estimate).

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