Re:Only one pair of integers satisfy the equation m^n = n^m
by Computeiful on Wednesday April 19, 2023 @10:34PM
(#35635680)
I noticed this interesting fact during my secondary school education. Additionally you can use this to prove that e is the point where a change in the exponent causes a larger result than a change in the base. E.g. (x+d)^y > x^(y+d) when y >= e for any real value d.
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Re:Only one pair of integers satisfy the equation m^n = n^m
by OscarCunningham on Thursday April 20, 2023 @06:45AM
(#35638262)
Only assuming y is also less than x.