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A comment on Formalising a new proof that the square root of two is irrational. Parent comment
Suppose K is non-empty, denote its minimum as k.
Consider the positive integer k' = k 3 - k = k (3 - 1).
Then k' < k (?!) and k' is also in K since k' 3 = 2 k - k 3, contradicting non-emptyness of K.
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I guess my questions are why k' < k and why k'√2 is positive?
Suppose K is non-empty, denote its minimum as k.
Consider the positive integer k' = k 3 - k = k (3 - 1).
Then k' < k (?!) and k' is also in K since k' 3 = 2 k - k 3, contradicting non-emptyness of K.
--
I guess my questions are why k' < k and why k'√2 is positive?