Re:Researchers thought this was a bug (Borwein integrals) [v...
by eutectic on Wednesday November 16, 2022 @09:03AM
(#33623047)
I guess it's a Gaussian, by the central limit theorem.
Re:Researchers thought this was a bug (Borwein integrals) [v...
by gugagore on Wednesday November 16, 2022 @11:00AM
(#33625308)
No, it can't be. This function has compact support, the Gaussian clearly does not.
You get a Gaussian by repeated convolution of the same function (and normalizing the width).
The equivalent question to what I asked is what's the pdf of X1 + X2/2 + X3/4 + ...
where Xi is iid unit uniform.
Re:Researchers thought this was a bug (Borwein integrals) [v...
by krackers on Thursday November 17, 2022 @02:42AM
(#33636053)
Do you mean `rect(2x) • 2rect(2x) • 4rect(4x)` .., both so that the limiting function is a dirac delta and the convolutions remain area preserving? Otherwise since the function you're convolving with keeps getting wider wouldn't the result also keep getting wider, so the support is no longer finite?
It might be possible to get a closed-form solution via an approach like [1]. (Out of curiosity, for rect convolved with itself, the intermediaries seem to be knwon as b-splines: https://www.chebfun.org/examples/approx/BSplineConv.html)
[1] https://math.stackexchange.com/questions/1254392/the-maximum...
rect(x) • rect(x/2) • rect(x/4) • ...
Where • is the convolution operator.
Unlike the series in the video, 1 + 1/2 + 1/4 + ... converges. So this function has compact support, and the value at 0 does not dip.
I expect it to be a https://en.m.wikipedia.org/wiki/Bump_function