Re:Deep symbolic regression for recurrent sequences
by amelius on Sunday January 30, 2022 @07:15PM
(#30142777)
Isn't that what you get if you add the formula for (0,0,0,0,0,0,1,...) to the formula for (1,1,2,3,5,8,13,...)?
Re:Deep symbolic regression for recurrent sequences
by nextaccountic on Sunday January 30, 2022 @05:49PM
(#30142062)
It found another formula that worked, what's the problem with that?
It added the term "quotient(u_{n-1} , n)" to the Fibonacci recursion, and claimed the resulting formula fit the data perfectly.
What?
EDIT: since people seem to be confused about why this is wrong... according to the graph, the sequence starts at n = 0. So the modified Fibonacci sequence I created is:
The computer says this formula fits it perfectly: Let n = 5: EDIT 2: hmm, contrary to the graph, the engine seems to assume the sequence starts at 1. So then we have I guess the formula works if "quotient" is defined as integer division?