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Re:Database character sets and collations explained – why ut... by Dylan16807 on Thursday January 06, 2022 @11:06PM (#29834695)
> Sorry, you can’t squeeze Unicode in that way, even unsynchronised: you fall just over 2½ bits short. No, reserving the 95 printable ASCII characters scuttles your hopes, meaning you get less than 1½ bits of that byte to use for the rest of Unicode, when you needed a touch over 4 bits.

So it depends on exactly what we mean by compatible, and that's why I removed it.

But in particular, the encoding I had in mind when I wrote that was one that allows most ASCII characters as the middle byte of a triplet. That way whether you truncate from beginning or end you'll never have a rogue byte successfully decode.

So something like: Lead bytes from C0-FF, middle bytes from 00-BF, final bytes from 00-1F or 7F-BF.

If you also exclude null, tab, newline, and line feed, that gives you 64 x 188 x 93, which is just enough for every code point.

But arguably that's not compatible enough because you couldn't search for single ASCII characters with a dumb byte-wise algorithm.

> Not quite. If you discarded ASCII compatibility, then you’d have almost four bits to spare, which is enough for a self-synchronising fixed-width 3-byte encoding (reserving the first bit of each byte to signal if it’s a start byte) or for an unsynchronised variable-width encoding of some kind; but to make it even 2-or-3 or 1-or-3 (rather than 1–3) bytes wide variable-width, you’d need four bits (3 + log₂ 2) for self-synchronisation, and you’re about 0.085 bits short. (1–3 bytes variable-width would require 3 + log₂ 3 ≈ 4.58 bits.)

I don't know where you got that equation but it's not the right one for the situation.

Here's a really simple encoding just to disprove it: Leading bytes encode the plane (17 options) plus two more bits into decimal values 0 through 67. Continuation bytes encode 7 bits into decimal values 128 through 255. 17 planes + 2 bits + 7 bits + 7 bits, perfect fit. The remaining values, 68-127, can be used for single byte (and two byte) encodings.

But also the definition I was using for self-synchronizing doesn't seem to match the one on wikipedia. My intent was a code where you can guarantee sync after a specific small number of bytes (unlike UTF-1). In particular, if you let standalone bytes and continuation bytes overlap each other, you can still guarantee sync within 3 bytes. This gives you lots of space to play with, and you could make a very useful encoding. You could have >150 single byte codepoints and thousands of double byte codepoints and fit everything else into three bytes.

Re:Database character sets and collations explained – why ut... by chrismorgan on Friday January 07, 2022 @01:37AM (#29835794)
My (3 + log₂ 2) came from reckoning that you needed one whole bit as a signal in each byte (3), and that the byte-width thing (log₂ 2) was extra to that. As you correctly point out, this was incorrect: the first byte doesn’t need one full bit of entropy to signal that it’s the first byte.