The core problem here is that you don't actually want to check if something is an object, but whether it matches the Human type. The correct way to do that is to define a type guard [0], for example:

  function isHuman(input: any): input is Human {
    return (
      Boolean(input) &&
      Object.prototype.hasOwnProperty.call(input, "name") &&
      Object.prototype.hasOwnProperty.call(input, "age")
    );
  }

There are libraries which can automate this for you which is the route I would recommend if you need to do this often. As you can see, the code to cover all edge cases such as `Object.create(null)` etc is not trivial.

[0] https://www.typescriptlang.org/docs/handbook/advanced-types....