Re:Ten Ways to Check if an Integer Is a Power Of Two in C
by mansr on Tuesday July 26, 2011 @10:23AM
(#2807419)
One they missed: (x & -x) == x
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Re:Ten Ways to Check if an Integer Is a Power Of Two in C
by chime on Tuesday July 26, 2011 @10:53AM
(#2807599)
That was #9:
int isPowerOfTwo (unsigned int x)
{
return ((x != 0) && !(x & (x - 1)));
}
Re:Ten Ways to Check if an Integer Is a Power Of Two in C
by cube13 on Tuesday July 26, 2011 @10:54AM
(#2807604)
This works for negative values of x, though.
It should be: ((x>0) && ((x & -x) == x))
Re:Ten Ways to Check if an Integer Is a Power Of Two in C
by quacker on Tuesday July 26, 2011 @10:53AM
(#2807601)
This is method 10 in the article, since -x is equivalent to ~x+1.
Re:Ten Ways to Check if an Integer Is a Power Of Two in C
by Jabbles on Tuesday July 26, 2011 @10:28AM
(#2807447)
Unfortunately this doesn't work for x=0.
Re:Ten Ways to Check if an Integer Is a Power Of Two in C
by rcfox on Tuesday July 26, 2011 @10:31AM
(#2807467)
2^-infinity == 0
Re:Ten Ways to Check if an Integer Is a Power Of Two in C
by Jabbles on Tuesday July 26, 2011 @10:44AM
(#2807551)
And 3 == 2^(log_2(3)).
Clearly we want to know if x is an integer power of 2.
Re:Ten Ways to Check if an Integer Is a Power Of Two in C
by wnoise on Tuesday July 26, 2011 @12:24PM
(#2808074)
2^(bitsize) == 0.
Edit: Yes, 1 << bitsize is undefined. But unsigned integers actually do have well-defined semantics on overflow, and multiplying by 2 enough times really does produce zero.
Re:Ten Ways to Check if an Integer Is a Power Of Two in C
by rcfox on Tuesday July 26, 2011 @12:48PM
(#2808224)
Actually, it's undefined behaviour. http://blog.regehr.org/archives/213
Re:Ten Ways to Check if an Integer Is a Power Of Two in C
by ot on Tuesday July 26, 2011 @12:49PM
(#2808229)
2^(bitsize) == 2^(bitsize)
If you meant 1 << (bitsize), that's undefined behaviour in C