Re:K0s – Zero Friction Kubernetes
by phist_mcgee on Monday November 16, 2020 @06:36PM
(#25118515)
Technically it is infinite times smaller than k3s or k8s :)
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Re:K0s – Zero Friction Kubernetes
by stonewareslord on Monday November 16, 2020 @11:02PM
(#25120154)
Technically, it would be an undefined number of times easier. n/0 is not infinite.
Technically, we may consider k0s to be the limit of a decreasing sequence of container orchestrators
`k8s, k3s, ... = k{x}s as x -> 0`
in which case we have 8/x -> +inf
Re:K0s – Zero Friction Kubernetes
by kimburgess on Tuesday November 17, 2020 @07:17AM
(#25122865)
Technically, neither the limit or full progression is defined by the information available. The set {k8, k3, k0} may be equally represented as a decreasing series of container orchestrators with reducing prime differences.
Re:K0s – Zero Friction Kubernetes
by oarsinsync on Tuesday November 17, 2020 @12:30PM
(#25126594)
I always thought that k3ks was so named because the symbol for 3 looks like a partial symbol for 8, indicating that it's k8s with a bit less.