But p - 2 is not the same as p + -2, and it's not clear in your example whether the former suffices or the latter is required. I can definitely imagine examples where the latter is required--certainly C clearly accommodates this usage--but IME it's nonetheless a rare scenario and not something that could, alone, justify always using signed offsets. Pointers are intrinsically neither signed nor unsigned; it's how you use them that matters.