. . ε
\ /
\ /
\ /
\ /
'._ _.'
^
Global optimum
In non-convex optimisation we can't make any assumption about the shape of the
error function: ,--. .--. ε
/ \ / \ ,--.
/ \ / \ / \ /
.' \ / \ / \ /
\ / \ / \ /
`--' \ / `--'
^ \ / ^
| `--' |
| ^ |
| | |
| | |
`--------- Local optima ----------'
"Optimisation" means that we're trying to find an optimum of a function - a
maximum or a minimum. We're usually interested in the minimum of a function,
particularly a function that represents the error of an approximator on a set
of training data. Generally we prefer to find a _global_ minimum of the error
function because then we can expect the resulting approximator to generalise better
to data that was not available during training.If the error function has a convex shape we're basically guaranteed to find its global minimum. In non-convex optimisation, we're guaranteed to get stuck to local minima.
(Ok, the above is a bit tongue in cheek, there's no _guarantee_ of getting stuck to local minima, but it's very likely).
Sorry to nitpick, but is this true? We are doing optimization here and a global minimum is just a better solution than a non-global minimum. Is there a connection to generalisation here?
But - there are some guarantees. Under PAC-Learning assumptions we can place an upper bound on the expected error as a function of the number of training examples and the size of the hypothesis space (the set of possible models). The maths is in a paper called Occam's Razor: https://www.sciencedirect.com/science/article/abs/pii/002001...
Unfortunately, PAC-Learning presupposes that the sampling distribution is the same as the real distribution, i.e. what I said above we can't know for sure.
In any case, I think most people would agree that a model that can reach the global minimum of training error on a large dataset has better chance to reach the global minimum of generalisation error (i.e. in the real world) than a model that gets stuck in local minima on the training data. Modulo assumptions.
In a motion planning or controls context, a local minima can often mean a configuration or path that is infeasible due to collision or wildly inefficient.
If your hill has a convex shape, then the marble will always roll up the bottom eventually.
It means there's a deterministic solution.
Longer explanation:
When you're optimizing a function in math, the function's solutions exist in N-dimensional space. If the space of solutions is a hyperplane in this space, and you want to find a value on that plane that minimizes the function, a convex plane will allow you to find the minimum every time, deterministically -- one way is to simply follow the negative gradient of the plane. A non-convex plane may have lots of holes or other shapes (e.g "saddle points"), so if you follow the negative gradient, you'll end up thinking you're at a minimum, but turns out you're only at a _local_ minimum and there may be another, better solution out there.
So whenever you see "convex" read: a best solution exists. Whenever you see "non-convex" read: an approximation is your best hope. Motion planning is non-convex.
From https://en.wikipedia.org/wiki/Convex_function: "Any local minimum of a convex function is also a global minimum. A strictly convex function will have at most one global minimum.[4]"
Your statement that > Motion planning is very much non-convex,
suggests to me that you are very much talking about the same thing. I understand convexity as in a shape. Why is convex good and concave bad in terms of optimization?
I don't want you to dumb down the answer too much as I am a trained Mechanical Engineer but then my major isn't math. Hope you understand :)