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A comment on It never makes sense to use foldl on lists in Haskell (2019). Parent comment

Re:It never makes sense to use foldl on lists in Haskell (2019) by dnautics on Saturday March 21, 2020 @12:12AM (#22644373)
It's also true in other languages. Erlang's foldr specifically annotates this in the documentation.
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Re:It never makes sense to use foldl on lists in Haskell (2019) by masklinn on Saturday March 21, 2020 @07:12AM (#22645778)
Erlang's foldr says exactly the opposite though, because Erlang is an eager language:

> foldl/3 is tail recursive and is usually preferred to foldr/3.

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Re:It never makes sense to use foldl on lists in Haskell (2019) by dnautics on Saturday March 21, 2020 @06:18PM (#22650690)
oh jeez I totally missed that. Thanks!
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Re:It never makes sense to use foldl on lists in Haskell (2019) by Dylan16807 on Saturday March 21, 2020 @02:33AM (#22644967)
The advantages to foldr in certain situations are very cross-language.

But foldl vs. foldl' is more about a badly-optimized implementation detail than anything else. It's very fair to qualify it as "in Haskell".

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