Re:BeOS: The Alternate Universe's Mac OS X
by tclancy on Thursday January 09, 2020 @01:47PM
(#22004151)
Wouldn't the median need to be over 1? I get your point but am feeling pedantic today.
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Re:BeOS: The Alternate Universe's Mac OS X
by projektfu on Thursday January 09, 2020 @02:03PM
(#22004308)
If more than 50% of personal computers have 1 or 0 users, then the median would be 1, assuming 0 users is less common than 1, regardless of how many users the remaining computers had.
Re:BeOS: The Alternate Universe's Mac OS X
by linza on Thursday January 09, 2020 @01:57PM
(#22004253)
If more than (or equal to) half of computers are used by only one person, then the median user count is 1, no?
Re:BeOS: The Alternate Universe's Mac OS X
by mulmen on Thursday January 09, 2020 @03:22PM
(#22005240)
If you have 3 PCs in the world, one with 0 users, one with 1 user and one with 23 users the median is 1.
Median is literally the middle, like a highway.
Re:BeOS: The Alternate Universe's Mac OS X
by BanazirGalbasi on Thursday January 09, 2020 @03:35PM
(#22005385)
They're just stating that having more than half of all computers with just 1 user guarantees that the median is 1.
Re:BeOS: The Alternate Universe's Mac OS X
by paulddraper on Friday January 10, 2020 @06:37AM
(#22010277)
No.
For example, suppose five computers have 1 user, 1 user, 1 user, 3 users, 300 users. The median is 1 user.
The claim of "median 1 user" just means more than half of computers has a single user.