(I'm assuming that population does not grow more than currently anticipated. I think this is fair because I later compare the number to our current Helium production which probably would scale up as well if the population were to significantly increase.)
The proton-proton chain reaction, the process that creates Helium-4 by fusing hydrogen plasma, releases 26.73 MeV of energy when creating a single helium atom out of 4 hydrogen atoms. [2] The molar mass of helium-4 is 4.002602 g/mol [3]. With this, we can do a quick trip to our favorite unit-aware calculator, units(1), to find how much Helium would be produced if our hypothetical future civilization used hydrogen fusion for all its energy needs:
(1460000 TWh / year) / 26.73 MeV / avogadro * 4.002602 g/mol
= 8157132.36 kg / year
Since Helium is a gas, it is more commonly measured in volume, so let's multiply that with its density at STP of 0.1786 g/L [4]: (1460000 TWh / year) / 26.73 MeV / avogadro * 4.002602 g/mol / (0.1786 g / liter)
= 45672633.63 m^3/year
Most Helium is produced by the United States (78% market share as of 2008 [4]), so let's just use their current production numbers as a comparison.> Helium production in the United States totaled 73 million cubic meters in 2014. [5]
That's 60% more than what would be produced by the future fusion reactors in my scenario. While it's true that I made a generous assumption by inflating the energy usage 10-fold, it appears that covering our Helium needs with fusion reactors is way more attainable than I imagined. We just need to cut back on wasting Helium a bit. The biggest "if" is, of course, if and when fusion reactors become economically viable.
[1] https://ourworldindata.org/energy-production-and-changing-en... [2] https://en.wikipedia.org/wiki/Proton%E2%80%93proton_chain_re... [3] https://en.wikipedia.org/wiki/Helium_atom [4] https://en.wikipedia.org/wiki/Helium [5] https://en.wikipedia.org/wiki/Helium_production_in_the_Unite...
Also current target fusion reactions are not based on the p-p chain. That is a much more difficult reaction to achieve. We're currently targeting D+T for first generation reactors. D+D is also very attractive because it is aneutronic and perhaps clever reactor design would allow for direct conversion of electricity. Energy in aneutronic fusion reactions is released as an acceleration of charged particles: a current. This current can be harvested through magnetic fields and thermal to electric efficiency can go up to 50% (maybe higher?). The actual details of this seem rather tricky since magnetic confinement devices are already tightly controlling the magnetic fields inside the reactor. It will be fun science and engineering for sure.
There are a few other commonly examined reactions, such as p+B11, but they're likely not going to be made viable reactions for energy production before D+T. These other reactions are all easier to achieve (in terms of Lawson criterion) than the stellar proton fusion chain.
I'll reuse your math with D+T=He-4+n and 3x energy production.
(4380000 TWh / year) / 17.59 MeV / avogadro * 4.002602 g/mol
= 41425784.21 kg / year
(4380000 TWh / year) / 17.59 MeV / avogadro * 4.002602 g/mol / (0.1786 g / liter)
= 231947280 m^3/year
Hopefully there aren't any glaring errors here. More views would be appreciated.1. as you acknowledged, the assumption that energy production would increase by tenfold
2. that all electrical energy produced would be made by fusion reactors
By the time we get to a state where a serious percentage of energy production was from fusion power we would likely be looking into more aggressively into other reactions and designs.
Even if we just said 30% of all energy used today was made from D+T fusion that would still be generating 10% of our current helium usage. That's a significant amount and a lot more than the 4 orders of magnitude that is oft cited online (https://www.reddit.com/r/askscience/comments/12r2s7/helium_i...). At a glance, it appears that the posts in this thread miscalculate how much fuel is necessary for a certain amount of energy. They glaze over that part of their calculations. I much prefer your dimensional analysis approach.
https://www.wolframalpha.com/input/?i=(.3++438000+TWh+%2F+year)+%2F+(17.59+MeV)+%2F+(avogadro%27s+number+1%2Fmol)++(4.002602+g%2Fmol)
(.3 * 438000 TWh / year) / (17.59 MeV) / (avogadro's number 1/mol) * (4.002602 g/mol)No, according to my source, it includes combustion.