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Re:Calculus for Beginners and Artists (2003) by baby on Sunday July 14, 2019 @12:51PM (#20434405)
1. X-b befomes 0 if x=b right?

2. This means anything multiplying this x-b becomes 0 as well when x=b right?

His definition of linear is also wrong in my book.

Linear: f(x) = a x

Affine: f(x) = a x + b

(For some a, b)

Re:Calculus for Beginners and Artists (2003) by cornstalks on Sunday July 14, 2019 @01:10PM (#20434492)
> His definition of linear is also wrong in my book.

There are two variations of "linear function". To quote https://en.wikipedia.org/wiki/Linear_function:

> In mathematics, the term linear function refers to two distinct but related notions:

> - In calculus and related areas, a linear function is [...] a polynomial function of degree one or zero.

> - In linear algebra, mathematical analysis, and functional analysis, a linear function is a linear map.

I personally prefer the terminology "linear function" for the former definition (polynomials of degree 1 or 0), and "linear transform" for the latter definition (a linear map).

Re:Calculus for Beginners and Artists (2003) by jacobolus on Sunday July 14, 2019 @07:12PM (#20436879)
What you are calling [“linear”, “affine”] are in some contexts called [“homogeneous linear”, “linear”] or the like.

This is not “wrong”, but just a different convention.

Re:Calculus for Beginners and Artists (2003) by kstenerud on Sunday July 14, 2019 @01:03PM (#20434458)
Is that comment for me or about the referenced page? If it's for me, I'm not sure what you're saying.
Re:Calculus for Beginners and Artists (2003) by baby on Sunday July 14, 2019 @01:24PM (#20434576)
I'm trying to explain what he meant. Which step don't you understand specifically in my comment?
Re:Calculus for Beginners and Artists (2003) by kstenerud on Sunday July 14, 2019 @01:46PM (#20434707)
I'm trying to understand why there's f(a) and f(b), why is b being subtracted from x, why it's divided by a-b, why there's a similar thing for f(a), why the two are being added, why the zero values are important, and what the whole thing actually means.
Re:Calculus for Beginners and Artists (2003) by jacobolus on Sunday July 14, 2019 @07:06PM (#20436845)
It’s simpler if you use 0 and 1 instead of a and b. If we want a linear function such that

f(0) = A, f(1) = B,

then the unique solution is

f(t) = (1-t)A + tB

The more general version with a and b is just composing this with a transformation of [a, b] into [0, 1]

Relevant keywords: linear interpolation, affine combination, barycentric coordinates.

Re:Calculus for Beginners and Artists (2003) by llamaz on Sunday July 14, 2019 @02:21PM (#20434925)
It's demonstrating how to find the line that passes through two points x=a, x=b on the function y=f(x).

Without having read the actual page, I assume he's going to move a and b close to eachother to approximate the tangent of the function at a point.

edit: In higher level math, you use circles/spheres or parabolas/paraboloids to approximate functions, but in high school level calculus you stick to using a straight line to approximate a function

Re:Calculus for Beginners and Artists (2003) by kstenerud on Sunday July 14, 2019 @02:54PM (#20435171)
Unfortunately, he doesn't do that. There's an even more complicated formula under that which is supposed to be related to the slope of some line and a ratio between b and a (I think?) and then I'm guessing he reduces it, but doesn't explain how he did it.

I've tried learning calculus 3-4 times during my life, using materials for an "absolute beginner", and this has always been my experience, as if one were teaching programming by going from "This is a variable. It can store data." directly to "A monad is a monoid in the category of endofunctors." To this day I have no idea what calculus even is, or what it's for.

Re:Calculus for Beginners and Artists (2003) by Xeanort on Sunday July 14, 2019 @05:32PM (#20436208)
You want a linear function f(x) such that f(a)=A and f(b)=B given a, b, A, B. A valid f(x) (actually it's the only one) is defined as

             x-b     x-a
    f(x) = A --- + B ---
             a-b     b-a
You can calculate f(a) and f(b) to confirm that it works.

However, I don't find this kind of guide any good for learning math...