Oh, that's hilarious. I tested this in Python where it worked fine and forgot that C has a "broken" modulo operator:

Python:

  >>> -1 % 20
  19

C:

  printf("%d\n", (-1 % 20));
  -1

Even worse, it still fails even on unsigned:

  printf("%d\n", ((unsigned int)0 - (unsigned int)1) % 20);
  15

So you still need to add N:

  printf("%d\n", ((unsigned int)0 - (unsigned int)1 + 20) % 20);
  19

Thanks for the reminder of humility.

(Side Note: For those reading this, the C operator isn't "broken", per se. There are three properties that modulo can adhere to but two of the three are mutually exclusive.)

C does not have a modulo operator. It has a remainder operator, which works perfectly fine. Calling C's `%` a 'broken modulo operator' is like calling `+` a 'broken minus operator'. Quite a few languages have separate operators, keywords, or functions for 'modulo' and 'remainder'.