How Craig Barton wishes he’d taught maths

Re:How Craig Barton wishes he’d taught maths by gizmo686 on Saturday February 09, 2019 @03:24PM (#19124376)

>A working definition of a space might be - you have a member in that space, you can get to every other member by just scalar mult.

Isn't this a 1 dimensional space. Eg. Consider the vector space R2 over R.

If you have the vector (1,0), there is no way to arrive at the vector (1,1) through just scalar multiplication.

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Re:How Craig Barton wishes he’d taught maths by dxbydt on Saturday February 09, 2019 @03:34PM (#19124428)

if you don’t give me basis how’ll i span the space ?

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Re:How Craig Barton wishes he’d taught maths by zazen on Saturday February 09, 2019 @04:01PM (#19124603)

You talked about having "a member" and getting to every other member with scalar multiplication only. But even given a 2-member basis for R2, how are you planning on using 2 members, with scalar multiplication only?

I'm afraid you have badly misremembered this stuff.

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Re:How Craig Barton wishes he’d taught maths by dxbydt on Saturday February 09, 2019 @04:07PM (#19124633)

you are right.

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