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A comment on Faster remainders when the divisor is a constant: beating compilers & libdivide. Parent comment

Re:Faster remainders when the divisor is a constant: beating... by Iwan-Zotow on Friday February 08, 2019 @10:57PM (#19120620)
see also https://math.stackexchange.com/questions/1251327/is-there-a-...
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Re:Faster remainders when the divisor is a constant: beating... by acqq on Sunday February 10, 2019 @05:50PM (#19130617)
Nice! If I'm not wrong, under many conditions this derivation gives even faster divisibility test then the one presented in the article we comment.
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