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Re:Faster remainders when the divisor is a constant: beating... by IshKebab on Friday February 08, 2019 @04:15PM (#19118755)
Clever. Is this possible with 64-bit numbers somehow?
Re:Faster remainders when the divisor is a constant: beating... by bloomer on Friday February 08, 2019 @07:27PM (#19119870)
Yes, the paper is general and covers the case for arbitrary bit size. 64-bit would require a 128-bit approximate inverse in general and the multiplication during computing the mod would extend that out another 64-bits. So would require three registers and two more multiplications on x64 I think. Socidont think it gains you anything in the general case. Bit for some divisors it might beat the traditional Granlund-Montgomery-Warren method when you could use a smaller approximate inverse.