Re:The DisplayPort Pin 20 Problem
by codedokode on Saturday May 26, 2018 @03:18PM
(#17163779)
There is a voltage drop on a diode, around 0.2 - 0.7 volts, cannot this become a problem?
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Then the supply before the diode supplies 3.3V + the voltage drop; for example 3.6V.
So now you need a 3.6V power regulator, in additition to the 3.3V one you likely already have for all the components built for 3.3V.
A Schottky will drop .3V; That's within the range (±10%) specified in the specs
Yes. But now you have given up all of your tolerance so you better have a perfect (or over-voltage) power supply. This means that you now have less choice in power supply.
As a parent commenter said, you could also put a diode for your circuitry. You would then have a single 3.7V supply.
Re:The DisplayPort Pin 20 Problem
by snovv_crash on Sunday May 27, 2018 @06:31AM
(#17166327)
And 10% higher power draw just for this one feature. No, there are better ways to solve this.