FizzBuzz in J, Explained

Re:FizzBuzz in J, Explained by Avshalom on Thursday January 19, 2017 @06:50PM (#13440539)

To translate that as literally as possible into Dyalog

  fizzbuzz ← {
    {(⍵ 'buzz' 'fizz' 'fizzbuzz')[1+2⊥0=3 5∘.|⍵]}¨⍵
  }

called as

  fizzbuzz ⍳100

or just

  {(⍵ 'buzz' 'fizz' 'fizzbuzz')[1+2⊥0=3 5∘.|⍵]}¨⍳100

with unnecessary parens

  {(⍵ 'buzz' 'fizz' 'fizzbuzz')[1+(2⊥(0=((3 5)∘.|⍵)))]}¨⍳100

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Re:FizzBuzz in J, Explained by jxy on Thursday January 19, 2017 @10:42PM (#13441593)

Since you are using ¨, ⍵ is a scalar, so you don't need the ∘.

Translated back to J

  ((;'Buzz';'Fizz';'FizzBuzz'"_){~2#.0=3 5|])"0>:i.100

The boxed list in J feels a bit cumbersome compared to mixed arrays in APL.

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Re:FizzBuzz in J, Explained by Avshalom on Friday January 20, 2017 @04:31PM (#13447125)

Fair enough. Like most APL I wrote it backwards until it worked.

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Re:FizzBuzz in J, Explained by lokedhs on Saturday January 21, 2017 @10:22AM (#13450398)

Works out-of-the box in GNU APL as well, if someone wants to try it with a free version of APL.

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Re:FizzBuzz in J, Explained by RodgerTheGreat on Saturday January 21, 2017 @12:05PM (#13450915)

To that end, my K version can be tweaked slightly to work with oK, an open-source interpreter based on k6:

    {(x;"Buzz";"Fizz";"FizzBuzz")@2 2/~3 5!\:x}'1+!20

k6 swapped the argument order of "mod" and made change of base into an overload of "/", rather than a named builtin. See it in action here:

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