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Re:A difference between Haskell and Common Lisp by fnordsensei on Monday December 21, 2015 @09:41AM (#10771227)
Is

    take 5 . filter p . drop 3
An anonymous function call in Haskell? I don't know the language (although it's on my to-learn sequence).
Re:A difference between Haskell and Common Lisp by marcosdumay on Monday December 21, 2015 @11:56AM (#10771996)
Yes. It's three anonymous ("take 5", "filter p" and "drop 3") functions composed by the "." operator, creating another anonymous function.

One of the types, for example:

take :: Int -> [a] -> [a]

What means a function that takes an Int argument and returns another function, that takes a list and returns a list of the same type.

Re:A difference between Haskell and Common Lisp by mietek on Monday December 21, 2015 @10:33AM (#10771505)
Yes, written in pointless style. You could make it less pointless by replacing the (.)s with a point.

    \xs -> take 5 (filter p (drop 3 xs))
https://wiki.haskell.org/Pointfree
Re:A difference between Haskell and Common Lisp by catnaroek on Monday December 21, 2015 @09:42AM (#10771241)
It's an anonymous function, which it not being called.
[deleted]
Re:A difference between Haskell and Common Lisp by catnaroek on Monday December 21, 2015 @11:10AM (#10771705)
You probably meant to reply to mietek.
Re:A difference between Haskell and Common Lisp by pja on Monday December 21, 2015 @12:04PM (#10772046)
ghci will (usually) tell you:

    phil@arod:~$ ghci
    GHCi, version 7.6.3: http://www.haskell.org/ghc/  :? for help
    Loading package ghc-prim ... linking ... done.
    Loading package integer-gmp ... linking ... done.
    Loading package base ... linking ... done.
    Prelude> :t take 5 . filter (\ _ -> True) . drop 3
    take 5 . filter (\ _ -> True) . drop 3 :: [a] -> [a]
So it’s a function from List of a to List of a