No, this does not mean that at all! An orbit asks for a centripetal force. In heliocentric systems this force is the gravity of the star (considering the gravity of the orbiting body to be negligible). Here, pairs of stars are kept into orbits and for each star the force that keeps it around is not only the force of gravity of the other star, but also that of its own (since it's not negligible any more). A third body can not have a stable motion around the "centre of mass" between those stars because there does not exist any force to keep it there. Any body between the orbiting stars will be under forces that will pull it towards the stars. It may at most stay "stable" in the middle, where the gravity forces of the around-orbiting stars cancel each other.
Thanks!
There could be stable point's in the middle, I don't know about that. Most certainly it can't be described by this approximation.
Edit: From Wikipedia:
>The triangular points (L4 and L5) are stable equilibria, provided that the ratio of M1/M2 is greater than 24.96.
So with a symmetric situation, where M1/M2=1 they wouldn't be stable either.
A example for a triple star system would be Alpha Centauri and Proxima Centauri, the closest star system to the Solar System. Alpha Centauri is a double star and Proxima Centauri orbits it at a huge distance, such that the seperation between the components of Alpha Centauri is no longer important for the orbit.
So it is certainly possible to find stable orbits, even in a very unusual star system like this one. But they are ( except in very rare cases), just elliptical orbits at huge distances.
It may be unlikely but it's certainly possible, right? Am I missing something that'd make this impossible? Because that would be incredibly cool!
edit: I'm assuming the masses of the two groups of stars would be roughly equal, in order for the centre of gravity to be in the "middle".
edit2: philosophical question: can this system still be described as heliocentric?