Yes, and these are effectively 3 different instructions sharing the same mnenomic. If you assemble them:

        mov     0x1000(%rax,%rax), %eax
        mov     %eax, 0x1000(%rax,%rax)
        mov     $7, %eax

You get:

        0000000000000000	8b840000100000  	movl	0x1000(%rax,%rax), %eax
        0000000000000007	89840000100000  	movl	%eax, 0x1000(%rax,%rax)
        000000000000000e	b807000000      	movl	$0x7, %eax

Which is basically 0x8b->Load, 0x89->Store, 0xb8->Constant.