Re:Clifford Algebra: A visual introduction (2014)
by reader5000 on Friday June 19, 2015 @04:49PM
(#9747595)
If I want to compute a derivative of a function expressed on a clifford algebra, does that make sense and is it possible?
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Re:Clifford Algebra: A visual introduction (2014)
by contravariant on Friday June 19, 2015 @08:52PM
(#9748485)
In the end the Clifford algebra is just a vector space, so that shouldn't be a problem. However it might become problematic that the dimension of the Clifford algebra is 2^n, where n is the dimension of the original space.