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A comment on 8^8 – Find another you. Parent comment

Re:8^8 – Find another you by supertruth on Friday May 15, 2015 @07:35PM (#9554321)
for the curious:

    (1 - reduce(operator.mul, map(lambda a: (8 ** 8.0 - a) / 8 ** 8, range(12000)))) * 100.0
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