Map<K,V> mkMap(int size) {
return size > threshold ? new HashMap<K,V>() : new TreeMap<K,V>();
}I'm still kind of unsure of why (Map m) => Int -> m isn't a valid type signature for this though..
Think about what it means if a type variable has no typeclass constraint: the type t isn't just a specific unknown type, it's literally any type. Similarly, C t => t isn't a specific unknown instance of a typeclass, it's any instance of that typeclass. If we tell Haskell that we're returning an instance C t => t and then try to give some concrete type, Haskell won't allow it, because it wants that type to encompass any possible type that implements C, not just the one we happened to use.
One way of making the above code work in Haskell is to use an existential type, which expresses that we're talking about some (not any) map type, but we'd have to wrap it inside a different constructor:
-- this expresses that a SomeMap constructor contains some kind
-- if Map, but we can't tell which one:
data SomeMap = SomeMap (forall m. Map m => m)
-- We can now express this by hiding the choice of Map inside the
-- SomeMap type:
mkMap :: Int -> SomeMap
mkMap size | size > threshold = SomeMap newHashMap
| otheriwse = SomeMap newTreeMap
which is, again, a solution with some advantages and some disadvantages. -- This might not be the best/cleanest way of writing it, as my
-- Idris is a little rusty, but this will work:
mkMap : (size: Int) -> (if size > threshold then HashMap else TreeMap)
mkMap size with (size > threshold)
| True = newHashMap
| False = newTreeMap
So yes, although again, other tradeoffs are made to allow this kind of radical expressiveness.
One place where you could write this easily is in a dynamically typed language:
That is exactly why this kind of research is interesting: we'd like to capture the flexibility of idioms that dynamic languages can sometimes afford us, with the extra safety and security guarantees of a static type system!