Re:Why is e^(pi i) = -1?
by timwiseman on Friday October 30, 2009 @11:40AM
(#912185)
So many texts on complex analysis simply define e^{i \theta} = \cos \theta + i \sin \theta without ever explaining how. This provides a good introduction to the reason behind with only minimal recourse to Calculus.
Another good description is discussed in "Visual complex Analysis" by Needham.
Another good description is discussed in "Visual complex Analysis" by Needham.